if 25C of charge passes through a conductor in 2s. a resistor of 3ohms is connected to the conductor. what will be the heat generated?

Ques. If 25Coulumbs of charge passes through a conductor in 2seconds. a resistor of 3ohms is connected to the conductor. what will be the heat generated?

To find the heat generated in the resistor, we can use Joule's law of heating, which states:

$H = I^2 R t$

where:

• H is the heat generated,
• $I$I is the current,
• $\mathrm{R\; is\; the\; resistance,\; and}$
• $t$t is the time.

First, we need to find the current using the formula:

$I = \frac{Q}{t}$

Given:

• $Q=25\text{C}$
• $t=2\text{s}$

$I = \frac{25 \, \text{C}}{2 \, \text{s}} = 12.5 \, \text{A}$

Current I ​=12.5A

Now, using the given resistance $R = 3 \, \Omega$ and time $t=2$, we can calculate the heat generated:

$H = (12.5 \, \text{A})^2 \times 3 \, \Omega \times 2 \, \text{s}$

$H = 156.25 \times 3 \times 2$

$H=937.5\text{J}$

So, the heat generated is $937.5 \, \text{J}$

Ans :  937.5J (joules).​